A 3-kg object undergoes an acceleration that is given by: a = 2 i + 5 j m/sec^2

Question

A 3-kg object undergoes an acceleration that is given by: a = 2 i + 5 j m/sec^2 Find the Force Vector acting on it and the magnitude of the force. (Hint: Use F = m a) A 3-kg object undergoes an acceleration that is given by: a = 2 i + 5 j m/sec^2 Find the Force Vector acting on it and the magnitude of the force. (Hint: Use F = m a) A 3-kg object undergoes an acceleration that is given by: a = 2 i + 5 j m/sec^2 Find the Force Vector acting on it and the magnitude of the force. (Hint: Use F = m a)

Explanation / Answer

F = m*a
= 3 Kg * (2 i + 5 j) m/s^2
= 6 i + 15 j N
This is the force vector

magnitude = sqrt (6^2 + 15^2)
= sqrt (261)
= 16 N
This is magnitude

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