A student launches a small rocket which stars from rest at ground level. At a he
ID: 1654732 • Letter: A
Question
A student launches a small rocket which stars from rest at ground level. At a height of h = 1.5 krn the rocket reaches a speed of v_f = 223 m/s. At that height the rocket runs out of fuel, so there is no longer any thrust propelling it. Take the positive direction to be upward in this problem. Assuming constant acceleration, what is the rocket's acceleration, in meters per second squared, during the period from its launch until it runs out of fuel? After the rocket's engine turns off at a height of h = 1.5 km, it continues to move upward due to the velocity that it reached. What is the rocket's acceleration, in meters per second squared, during the period from engine shutoff until it returns to the ground? Ignore air resistance. a_2 =Explanation / Answer
A) a = V²/(2y)
= 223²/(2*1500)
= 16.6 m/s²
B) a = gravity
=> a2 = -g = -9.8 m/sec²
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