A parcel of air moving in a straight tube with a constant acceleration of -2.80

Question

A parcel of air moving in a straight tube with a constant acceleration of -2.80 m/s^2 and has a velocity of 11.5 m/s at 10: 05: 00 a.m. (a) What is its velocity at 10: 05: 01 a.m.? 11.5 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) What is its velocity at 10: 05: 04 a.m.? 2.5 Your response differs from the correct answer by more than 100%. m/s (c) What is Its velocity at 10: 04: 59 a.m.? 17.5 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s

Explanation / Answer

a) V = u + at

v = 11.5 - 2.8*1

v = 8.7 m/s

b) v = 11.5 - 2.8*4 = 0.3 m/s

(c) v = 11.5 + 2.8*1 = 14.3 m/s

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