An isolated, irregularly shaped piece of platinum carries -8.15 × 10-9 C of char

Question

An isolated, irregularly shaped piece of platinum carries -8.15 × 10-9 C of charge and is in electric equilibrium. The size of this body is about 4 mm. When the electric potential at some point on the metal's surface has the value V, the potential at a different point on the surface (indicate one):

An isolated, irregularly shaped piece of platinum carries -8.15 x 109 C of charge and is in electric equilibrium. The size of this body is about 4 mm. When the electric potential at some point on the metal's surface has the value V, the potential at a different point on the surface (indicate one): O always differs from V O may equal v. O equalsv When the electric field strength at some point on the body's surface has the value E, the field strength at a different point on the surface (indicate one): O equals E. O equals o. O may equal E. O always differs from E. Calculate the potential at a distance of 6.75 m from the center of the charged piece of platinum Number

Explanation / Answer

1) equals V

A charged metal surface is an equipotential surface that is why the potential everywhere on the surface will be equal irrespective of the shape of the metallic piece.

2) may equal E

Though the potential is same everywhere on the metallic surface, due to the irregular shape of the piece of platinum the electric field may vary, but at some 2 given points it may also be equal.

3)V = kQ/r

where k = 9*109 m/F , Q = -8.15*10-9 C and r = 6.75 m

V = 9*109 m/F * (-8.15*10-9) C / 6.75 m = -10.87 V

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