An ideal parallel-plate capacitor is charged to 20 V and 80 C, then disconnected

Question

An ideal parallel-plate capacitor is charged to 20 V and 80 C, then disconnected from the battery. The dielectric is transformed to be half as thick and have only one-third the permittivity. The plates are then pushed together to fit it. What are the new voltage and charge? An ideal parallel-plate capacitor is charged to 20 V and 80 C, then disconnected from the battery. The dielectric is transformed to be half as thick and have only one-third the permittivity. The plates are then pushed together to fit it. What are the new voltage and charge?

Explanation / Answer

since the dielectric is not removed from the capacitor ,the charge remains constant

and potential difference increases by a factor

so new charges are 80 uC and new voltage is 3*20 = 60 V

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