The electric field at point P due to a point charge Q as a distance R away has m

Question

The electric field at point P due to a point charge Q as a distance R away has magnitude E. In order to decide the magnitude of the field at P, you could (explain) double the charge to 2Q and at the same time reduce the distance to R/2. double the distance to 2R. double the distance to R/2. double the distance to R/4. double the charge to 2Q In Fig., four charges are placed at the corners of a square of side 8 cm. What is the electrostatic potential energy of this system relative to infinity? An electron was accelerated from rest through a potential difference of 1, 500 V. What is its speed? 2.3 times 10^7 m/s 1.9 times 10^7 m/s 1.9 times 10^7 m/s 1.9 times 10^7 m/s

Explanation / Answer

Q1.
Option E, double the charge to 2Q.

Electric field E = F/Q
=> E = 1/4piE0 * Q/R^2

Here,
1/4piE0 is constant
R^2 is inversely prop to E
and Q is directly prop to E

So, in order to double E, we should double the value of Q.

Pls post other questions separately.

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