My Netes A projectile is launched with an initial speed of 54.0 m/s at an angle

Question

My Netes A projectile is launched with an initial speed of 54.0 m/s at an angle of 33.0 above the horizontal. The protectile lands on a hillside 3.80 s later. Neglect air friction. (Assume that the +x-axis is to the right and the +y-axis is up along the page) (a) What is the projectile's velocity at the highest point of its trajectory? magnitude direction m/s counterclockwise from the + x-axis (b) What is the straight-line distance from where the projectile was launched to where it hits its target?

Explanation / Answer

Part a) v = 54 * cos 33 = 45.2882 m/s

Part a) theta = 0.00 deg counterclockwise from the + x-axis

Part b) x = 172.0952 m

x1 = 54 * sin 33 * 3.80 - 0.5 * 9.8 * 3.8*3.8 = 41.00 m

d = sqrt ( 172.0952 ^2 + 41 ^2 ) = 176.9126322 m ===============ANSWER)

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