do all the parts please.B to D o calculate the momeht oT a Couple ahd the het mo

Question

do all the parts please.B to D

o calculate the momeht oT a Couple ahd the het moment of multiple couples Part B - Finding the net moment due to two couples A couple is defined as two paaeforces separated by a perpendicular distance d that have the same magnitudes but opposite directions The image below shows a beam subject to two couples, Fi = 610 N and F2 830 N ur The dimensions are 2 1 = 1.50 m, z2 1.30 m, h 0.13 m Figure 4 of5 =43° , and = 270 What is the net moment on the beam due to the two couples? Express your answer to three significant figures and include the appropriate units Hints Me = 10 N·m Submit My Answers Give Up Incorrect, Iry Again, 5 attempts remaining

Explanation / Answer

B. given F1 = 610 N
F2 = 830 N
x1 = 1.5 m
x2 = 1.3 m
h = 0.13 m
theta = 43 deg
phi = 27 deg

now net moment in the beam = [F2*cos(phi) + F1*cos(theta)](x1 + x2) - [F1cos(theta) + F2cos(phi)]*x2 = [F1cos(theta) + F2cos(phi)]*x1
M = (610*cos(43) + 830*cos(27))*1.5 = 1778.491759 Nm

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