T. AO 1.41. BO 2.04 × 10 FO 904 x 107 DO 4.30 × 107 EO 6.23 × 107 GO 1.31 x 10 H
ID: 1656843 • Letter: T
Question
T. AO 1.41. BO 2.04 × 10 FO 904 x 107 DO 4.30 × 107 EO 6.23 × 107 GO 1.31 x 10 HO 1.90 x 10 5p/ (e24p40_ce) A point charge q = 5.00× 10-6 C is placed at the center of a electrically neutral, spherical conducting shell with inner radius a - 14.0 cm and outer radius b 29.4 cm. What charge appears on the inner surface of the shell? (in c) 8. A1.64 × 10-6B0-238 x 10-6C0-3.45 × 10-6 D0-500 x 10-6E0- O- GO-1.52 × 10-5H0-2.21 x 10-5 7.25 × 10-6F 1.05× 10 -5 5 pt What charge appears on the outer surface? in C) 9. AO 3.92 × 10-6 4.42 × 10-6 CO 5.00 x 10-6 DO 5.65×10-6 EO 6.38×10-6 FO 7.21x10-6 GO 8.15 × 10-6 HO 9.21 × 10-6Explanation / Answer
8.
on the inner surface , due to induction , charge on the inner surface will be exactly opposite in sense and equal in magnitude to the charge at the center.
hence - 5 x 10-6 C
9.
To have the spherical shell neutral , the total charge on it must add to zero. since inner surface has a charge of - 5 x 10-6 C, the outer gains an equal positive charge so as to have the total sum as zero
so 5 x 10-6 C
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