In tests on earth a lunar surface exploration vehicle (mass = 5.23 × 103 kg) ach

Question

In tests on earth a lunar surface exploration vehicle (mass = 5.23 × 103 kg) achieves a forward acceleration of 0.200 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.56 × 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon? In tests on earth a lunar surface exploration vehicle (mass = 5.23 × 103 kg) achieves a forward acceleration of 0.200 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.56 × 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon?

Explanation / Answer

Given,

Mass of vehicle, m = 5.23 x 103 kg

Acceleration, a = 0.200 m/s2

Force, F = 1.56 x 1000 N

Force = mass x acceleration = 5.23 x 1000 x 0.200 = 1046 N

So, the magnitude of frictional force, Ffriction = 1560 - 1046 = 514 N

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