a. Determine the lm b. Determine the total momentum before I c. Was momentu m co

Question

a. Determine the lm b. Determine the total momentum before I c. Was momentu m conserved in this collision? Justify your answer. s are on a low-friction track. The first is moving to the right at lo Two identical cart towards the second. The second cart is at rest. After the collision, the cart together. What is the speed of the two carts after the collsion? Show your work s stick . A 2.0 kg cart and a 3.0 kg cart colide on a low-friction track. The 3.0kg cart is intily moving at 1.o m/s to the right, but after the collision it is moving at 5.0 m/s to the After the collision, the 2.0 kg cart is moving to the right at 3.0 m/s. What was the 2.0ke cart's initial velocity?

Explanation / Answer

Q1. Given:

Mass of 1st cart= m1=m

mass of 2nd cart=m2=m

speed of 1st cart = v1= 10 i

speed of 2nd cart =v2=0

now the both carts collided with each other. momentum is conserved

so momentum before collission = momentum after collission

i.e. momentum of 1st cart before collission + momentum of 2nd cart before collission= momentum of both carts after the collission

so, m x 10 i + m x0 = (m+m) x v ( as both carts move together with same speed)

so, v= 5i

so both carts will move with a speed of 5 m/s towards right after the collission.

Q2.Given:

Mass of 1st cart= m1=3 kg

mass of 2nd cart=m2=2 kg

speed of 1st cart before collission= u1= 1 i

speed of 2nd cart before collission=u2=v =?

speed of 1st cart after collission= v1= 5 i

speed of 2nd cart after collission=v2=3i

now the both carts collided with each other. momentum is conserved

so momentum before collission = momentum after collission

i.e. momentum of 1st cart before collission + momentum of 2nd cart before collission=momentum of 1st cart after collission + momentum of 2nd cart after collission

so, 3 x 1 i + 2 xv = 3 x 5i + 2 x 3i

so, 2v= 18i

so v = 9i

so 2kg cart's initial velocity was = 9 m/s towards right

ALL THE BEST IN THE COURSE WORK

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