s Management | Help s II Begin Date: 9/12/2016 12:00:00 AM-Due Date: 926/2017 8
ID: 1658098 • Letter: S
Question
s Management | Help s II Begin Date: 9/12/2016 12:00:00 AM-Due Date: 926/2017 8 00:00 AM End Date: 12/15/2017 11.59:00 PM %) Problem 19: A block with mass mi-3 kg rests on the surface of a rizontal table which has a coefficient of kinetic friction of = 0.52. A second lock wth a mass m2-8.2 kg is connected to the first by an ideal pulley system ch that the second block is hanging vertically. The second block is released and otion occurs M. Ctheespertta.com rt (a) Using the variable T to represent tension, wite an expression for the sum of the forces in the y direction, EF, for block 2 Part (b) Using the variable T to represent tension, wite an expression for the sum of the forces in the x direction, EF, for block 1 Grade Summary Deductions 96% Submissioms ay END m2 BACKSPACECLEAK Submit Hint | Feedback. ,m.erJ Hinn:,deduction pet hint Hints temann 20% Part (c) Wrte an expression fo the cable connecting the masses is ideal ) the magnitude of the acceleration oft lock 2 a, m terms of the acceleration of block 1 20% Part (d) Write an expression using the variables provided for the magnitude of the tenson 20". Past (e) What is the tension, Tin Neston? orce. TExplanation / Answer
a) Fy = T - g*m2
b) Fx = T - µ*g*m1
c) a2 = a1
d) T = [g*m1*m2*(1+µ)]/(m1+m2)
e) T = 59.54 N
f) a = g*[1 - (1+µ)/(1+m2/m1)] = 2.538 m/s²
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