s A particle has a charge of q-+4.9 C and is located at the origin. As the drawi
ID: 1883219 • Letter: S
Question
s A particle has a charge of q-+4.9 C and is located at the origin. As the drawing shows, an electric field of Ex +212 N/C exists along the +x axis. A magnetic field also exists, and its x and y components are Bx +1.4T and By +1.9 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b) moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s. ty +x E, (a)FE By (b) FE By (c) Fe-Explanation / Answer
a) Fe = q*E
= 4.9*10^-6*212
= 1.04*10^-3 N (towards +x axis)
FBx = q*v*B*sin(theta) (here theta is the angle between v and B)
= 0 (since v = 0 )
FBy = q*v*B*sin(theta)
= 0 (since v = 0 )
b)
Fe = q*E
= 4.9*10^-6*212
= 1.04*10^-3 N (towards +x axis)
FBx = q*v*B*sin(theta) (here theta is the angle between v and B)
= q*v*B*sin(0)
= 0
FBy = q*v*B*sin(theta)
= 0
c) Fe = q*E
= 4.9*10^-6*212
= 1.04*10^-3 N (towards +x axis)
FBx = q*v*By*sin(90)
= 4.9*10^-6*345*1.9
= 3.21*10^-3 N (towards -x axis)
FBy = q*v*Bx*sin(90)
= 4.9*10^-6*345*1.4
= 2.37*10^-3 N (towards +y axis)
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