In the figure, the point charges are located at the corners of an equillateral t

Question

In the figure, the point charges are located at the corners of an equillateral triangle 29 cm on a side. A). Find the magnitude of the electric field in N/C at the location of Qa, given that Qb=9.3 micro Coulomb and Qc = -4.6 micro coulomb. B). Find the direction of the electric field at Qa in degrees above the negative x-axis with origin at Qa. C). What is the magnitude of the force in N on Qa, given that Qa=1.1 nC? D). What is the direction of the force on Qa in degrees above the negative x axis with origin at Qa? (20%) P equilateral triangle 29 cm on a side. 2: In the figure, the point charges are located at the of an la ge Otheexpertta.co 25% Part (a) Find the magnitude of the electric field in NC at the location of qa, given that q,-9.3 pC and qc-46 pC Grade Summary Deductions0 Potential100 sin0 cotan0 asinacos0 atan0 acotan0 sinh0 (3 per attempt) 0 Hint I give up Hints: C-deduction per hint. Hints remaining- 25% Part (b) Find the direction of the electric field at in degrees above the negative x-axis with origin at 9a. 25% Part (c) what is the magnitude of the force in N on qa, given that q,-1.1 nC? -a 25% Part (d) what is the direction of the force on a in degrees above the negative x-axis with origin at qa?

Explanation / Answer

A) Electric field due to qb,

Eb = kqb/r^2 = 9e9*9.3e-6/0.29^2 = 995244 N/C

Electric field due to qc

Ec = kqc/r^2 = 9e9*4.6e-6/0.29^2 = 492271 N/C

Enet = sqrt(995244^2+492271^2 +2*995244*492271*cos 120 degree)

= 861923 N/C

B) angle = arctan [(995244-492271) sin 60 degree /((995244+492271) cos 60 degree)]

= 30.36 degree above - x axis

C) F = qE

= 1.1e-9*861923

= 0.000948 N

D) direction angle of force= direction of electric field as qa is positive

= 30.36 degree above - x axis

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