Unbeknownst to most students, every time the school floors are waxed, the physic

Question

Unbeknownst to most students, every time the school floors are waxed, the physics teachers get together to have a barrel of phun doing friction experiments in their socks (uhm - they do have clothes on; its just that they don't have any shoes on their feet). On one occasion, Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then with what force (in Newtons) must Mr. London be pulling?

Explanation / Answer

Given,

mS = 84 kg ; a = 1.2 m/s^2 ; u = 0.35

The frictinal force is:

Ff = u mg = 0.35 x 84 x 9.8 = 288.12

F = ma = 84 x 1.2 = 100.8

Applied force will be:

Fapp = Ff + F

Fapp = 288.12 + 100.8 = 388.92 N

Hence, Fapp = 388.92 N = 389 N(aprox)

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