Chaper 18PSS 18.1: Calculation of Potential PSS 18.1: Calculation of Potential W
ID: 1659417 • Letter: C
Question
Chaper 18PSS 18.1: Calculation of Potential PSS 18.1: Calculation of Potential What is the electric potential at point 8? Express your answer in volts Learning Goal: Hints To apply Problem-Solving Strategy 18.1 Calculation of potential Va-115 V Three point charges with values gi-800 nC nC, and g -7.00 nC are placed on three consecutive corners of a square whose side moasums 8=2.00 m Point A lios at the fourth corner of the square, diagonally across from q2. Point B lies at the center of the square. What are the values of the electrie potential at point A | #300 My Answers Give Up Correct and at point B? How much energy (supplied as work) is required to move a test charge qu 2.00 nC from point A to point B? Assume the zero of electric potential is chosen to be at infinity Part E How much energy W is required to move a test charge of 200 nC fom point A to point 87 Express your answer numerically in joules. Hints of 1 ubmit My Answers Give Up REFLECT Think about whether your results make sense Part F This queston will be shown aer you corrclete previous question/s)Explanation / Answer
Point B is at equal distance from each of the sources q1, q2, q3 s= sqrt(2) m
The potentail at a distance s from charge q , V = kq/r
potenial at B due to each of the charges
V1 = 9.0e9 * 8.0e-9 /sqrt(2) = 50.91 V
V2 = 9.0e9 * 3.0e-9 /sqrt(2) = 19.09 V
V3 = 9.0e9 * 7.0e-9 /sqrt(2) = 44.55 V
The potentail at B from all the charges is obtained by superposition rule
= 50.91 + 19.09 + 44.55 = 114.55 V
at A distance for q1 and q3 s= 2 m and for q3 s = sqrt(8)
potential at A
V1 = 9.0e9 * 8.0e-9 /2 = 36 V
V2 = 9.0e9 * 3.0e-9 /sqrt(8) = 9.55 V
V3 = 9.0e9 * 7.0e-9 /2 = 31.5 V
Potential at A = 36 + 9.55 + 31.5 = 77.05 V
Potential diff betwen A and B = 114.55 - 77.05 = 37.5 V
work done in moving a charge of 2 nC from A to B = 37.5 * 2.0e-9 = 75e-9 J
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