Hwk 5 9/29/2017 2. -/4 pointsSerCP10 5.P.004 A shopper in a supermarket pushes a

Question

Hwk 5 9/29/2017 2. -/4 pointsSerCP10 5.P.004 A shopper in a supermarket pushes a cart with a force of 36 N directed at an angle of 250 below the horizontal. The force is just sufficient to overcome various frictional forces, so the cart moves at constant speed. (a) Find the work done by the shopper as she moves down a 45.0-m length aisle. (b) What is the net work done on the cart? Why? This answer has not been graded yet. (c) The shopper goes down the next aisle, pushing horizontally and maintaining the same as before. If the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same? What about the work done on the cart by the shopper? speed This answer has not been graded yet. Need Help? L Readin

Explanation / Answer

A) work done = F s cos theta

= 36*45* cos 25 degree

= 1468 N

B) net work done = 0J

Because change in velocity is zero. So change in KE is also zero.

C) work done on cart by shopper doesn't change too. It is because work done by friction is also same and absolute value of work by friction and shopper are equal.

So force decreases as cos theta component imcreased to 1.

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