A bear is tracked as she wanders around in South Dakota First, the bear travels

Question

A bear is tracked as she wanders around in South Dakota First, the bear travels through a displacement D = 8.00 miles, directed 30°N of w Then the bear undergoes a displacement D2 = 12.0 miles, directed 20° w of s. Thus, the bear undergoes a resultant displacement R = D+ D. In the following, assume that the ty direction is defined as due North and that the +x direction is defined as due East, as shown in the figure 16. True or False: | R-14 + ? a. True b. False 17. True or False: D,x and D2, are both positive? a. True b. False 18. Displacement D2 has an x component-vector equal to a. 11.3 miles 1 b. -12.0 miles c. 4.10 milesI d. 11.3 miles e. 4.10 miles. 19. The bear's resultant displacement has a magnitude of a. 20.0 miles. b. 4.00 miles. c. 18.6 miles. d. 18.6 miles. e. 13.2 miles. 20. The bear's resultant displacement is directed a. due North-East. b. 33.4° W of S. c. 56.6 W of N d. 33.4° S of W e. 56.6° N of E.

Explanation / Answer

16) False    |R|= sqrt[D1^1 + D2^2 + 2*D1*D2*cos(Theta)]

|D1 + D2| = sqrt[D1^2 + D2^2]

17) False    D1x and D2x both are negative

18) D2x = -12*cos20 = -11.3 miles i^   (Option a)

19) R = sqrt[8^2 + 12^2 + 2*8*12*cos50] = 18.2 miles

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