A beam of visible light has a wavelength of 435 nm and shines perpendicularly on

Question

A beam of visible light has a wavelength of 435 nm and shines perpendicularly on a surface. As a result, there are 2.7 x 10 18 photons per second striking the surface. By using the impulse-momentum theorem (Section 7.1), obtain the average force that this beam applies to the surface when (a) the surface is a mirror, so the momentum of each photon is reversed after reflection, and (b) the surface is black, so each photon is absorbed and there are no refelcted photons.

Please explain how to solve. Thanks!

Explanation / Answer

h/p= -------1

p/t=f-------2

a)as change in the direction of velocity

p=p1-(p2)=2p   

from eq 1

p=1.52*10-27

2p=3.04*10-27 for 1 photon

for all

n(2p)=8.208^10-9

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