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A beam of mass mb = 10.0 kg, is suspended from the ceiling by a single rope. It

ID: 2150770 • Letter: A

Question

A beam of mass mb = 10.0 kg, is suspended from the ceiling by a single rope. It has a mass of m2 = 40.0 kg attached at one end and an unknown mass m1 attached at the other. The beam has a length of L = 3 m, it is in static equilibrium, and it is horizontal, as shown in the figure above. The tension in the rope is T = 637 N.

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(a) Determine the unknown mass m1, at the left end of the beam.

m1= ______________kg

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(b) Determine the distance, x, from the left end of the beam to the point where the rope is attached. Note: take the torque about the left end of the beam.

x = _______________m

Explanation / Answer

a) in vertical , balancing forces

T = mbg + m1g + m2g

637/g = 10 + m1 + 40

m1 + 50 = 65

m1 = 15kg

b) balancing moment about the point where 15kg mass (m1) is attached,

1.5 x 10g + 3 x 40g - x X 637 = 0

147 + 1176 = 637x

x = 1323/637 = 2.08m

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