2. A 20-kg block is pushed against a vertical wall by a horizontal force of 150
ID: 1659973 • Letter: 2
Question
Explanation / Answer
Given , normal reaction force on wall (N) = 150 N
s = 0.65 , k = 0.43, mass(m) = 20 kg
Static frictional force (fs)= s* N = 0.65*150 = 97.5 N
Kinetic frictional force (fk)= k*N = 0.43*150 = 64.5 N
Weight acting downward of the block(W) = 20*9.8 = 196 N
If the block is about to slide down , Kinetic frictional force acts on the block
Using Newton second law,
W - fk = m*a
196 - 64.5 = 20*a
a = 6.58 m/s^2
Therefore , answer) option C) the block slides down with an acceleration of 6.58 m/s^2
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