An experimental bicycle wheel is placed on a test stand so that it is free to tu

Question

An experimental bicycle wheel is placed on a test stand so that it is free to turn on its axle. If a constant net torque of 5.50 Nm is applied to the tire for 2.00 s , the angular speed of the tire increases from zero to 105 rev/min . The external torque is then removed, and the wheel is brought to rest in 125 s by friction in its bearings.

a) Compute the moment of inertia of the wheel about the axis of rotation.

b) Compute the friction torque.

c) Compute the total number of revolutions made by the wheel in the 125 s time interval.

Explanation / Answer

= 105rev/min * 2rad/rev * 1min/60s = 11 rad/s

= / t = 11rad/s / 2.00s = 5.5 rad/s²

A) torque = I, so

5.50 N·m = I * 5.5rad/s², and

I = 1 kg·m²

B) Now = 1kg·m² * 11rad/s / 125s = 0.088 N·m

C) = *t - ½t² = 11rad/s*125s - ½(11rad/s/125s)(125s)²

= 687.5 rad = 109.4 revs

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