An experimental bicycle wheel is placed on a test stand so that it is free to tu

Question

An experimental bicycle wheel is placed on a test stand so that it is free to turn on its axle. If a constant net torque of 5.00 Nm is applied to the tire for 2.00s, the angular speed of the tire increases from 0 to 100 rev/min. The external torque is then removed, and the wheel is brought to rest by friction in its bearings in 125s. Compute (a) the moment of inertia of the wheel about the rotational axis; (b) the friction torque; (c) the total number of revolutions made by the wheel in the 125-s time interval.

Explanation / Answer

1)Torque=moment of inertia * angular accelaration => 5=I*(100-0)/2 =>I=0.1kg.m² 2)friction torque= I * angular acc. = 0.1*(100-0)/125 =0.08Nm 3)no of revolutions= (1/2)(100/125)(125)² =6250rev

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