Three charged marbles are qlued to a n distanca r2.00 cm to the right of the mar
ID: 1660735 • Letter: T
Question
Three charged marbles are qlued to a n distanca r2.00 cm to the right of the marble 92, as shown. Calculate the magnitude of the electric fleld 266'10 "8X on surface and are placed in the diagram as shown. The charges or each marble are Q:6.35 uc, g2-1.54 pC, and Q, 1.51 pC, Marble q1 is a distance ri-J 00 cm to the left or the marole while marble Q2 is a distance r-1.00 cm to the laft ofthe center marble. the total or point Ano her marble i placed 1 crn to the left the midd e marble. If thi new rnarble has charge uf 3 ByC calculate magnitude and rectlun of the force on it.Explanation / Answer
E = kQ / d²
At the point in question, the field due to q1 is positive (to the right), due to q2 is negative (to the left) and due to q3 is positive (to the right). Then
E = 8.99*10^9N·m²/C² * (6.35/(0.02m)² - 1.54/(0.01m)² + 1.51/(0.03m)²) * 1*10^-6C
E = 1.427*10^8 N/C field at 1 cm left of center marble
For fourth marble:
F = q*E = 3.80*10^-6C * 1.427910^8N/C = 542.26 N
and the direction is "to the right."
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