Three capacitors having capacitances of 8.1F , 8.9F , and 5.0F are connected in

Question

Three capacitors having capacitances of 8.1F , 8.9F , and 5.0F are connected in series across a 36-V potential difference.

a) What is the charge on the 5.0?F capacitor?

b)The capacitors are disconnected from the potential difference without allowing them to discharge. They are then reconnected in parallel with each other, with the positively charged plates connected together. What is the voltage across each capacitor in the parallel combination?

c)What is the total energy now stored in the capacitors?

Three capacitors having capacitances of 8.1MuF , 8.9MuF , and 5.0MuF are connected in series across a 36-V potential difference. Part A What is the charge on the 5.0MuF capacitor? Express your answer using two significant figures. Part B What is the total energy now stored in the capacitors? Express your answer using two significant figures. U= J

Explanation / Answer

equivalent capacitance

1/Ceq=1/8.1 +1/8.9 +1/5

Ceq=2.3 uF

Total Charge

Q=CeqV =2.3*10-6*36=8.26*10-5C

a)

charge on 5 uF is

Q3=Q=8.26*10-5C

b)

total charge before potential difference disconnection

Qtot=3*(8.26*10-5)=2.478*10-4 C

equivalent capacitance in parallel

Ceq=8.1+8.9+5 =22 uF

Voltage across each capacitor is

V1=V2=V3=Qt//Ceq =(2.478*10-4)/(22*10-6)=11.26 Volts

c)

Total energy in parallel

U=(1/2)QV =(1/2)(2.478*10-4)(11.26)

U=1.4*10-3 J

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