Question No 7: A sinusoidal electromagnetic wave having magnetic field of amplit

Question

Question No 7: A sinusoidal electromagnetic wave having magnetic field of amplitude Bnash 1.25)iT and a wavelength of -432nm is traveling in the + x direct speed of light (c).(3+3+4+3+3 16 points ion with (a) What is the frequency (f) of this wave? - 3.10 432.TOs..jo.94.io'"H (b) What is the amplitude of the associated electric field (Eesa)? (c) Write the wave equations for the electric and magu tions of a and t (hint: Look at wave equation in formula sheet: y(r t) could be E(r.t) or B(x,t).) (d) Calculate average energy (ua) of the beam 2(TT-10-7) (e) Calculate the intensity (Sa) of the bcam ,(1845)

Explanation / Answer

average intensity of EM wave is given by

c*B^2/(2*mu)

where c=speed of light

B=amplitude of magnetic field

mu=magnetic permeability=4*pi*10^(-7)

using the given values,

average intensity=3*10^8*(1.25*10^(-6))^2/(2*4*pi*10^(-7))=186.51 W/m^2

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