014 (part 2 of 3) 10.0 points Express the length of a marathon run of 26 mi 385

Question

014 (part 2 of 3) 10.0 points Express the length of a marathon run of 26 mi 385 yd in meters. Answer in units of m. 015 (part 3 of 3) 10.0 points Express the distance 3273 mi from Seattle, Washington, to Miami, Florida, in meters. Answer in units of m. 016 10.0 points The position r has the dimensions of [L] (i.e., length). The velocity v has the dimensions of LI/[T] (i.e., length/time). The acceleration a has the dimensions of [L]/T]2. Which of the following quantities has the same dimensions as a? 1. u2 2. 22/ 5. ru/a 017 10.0 points The volume of an object is given as a function oftime by V = A+- +Ct4 Find the dimension of the constant C. 1. L3/T 4. L/T 5. L/T

Explanation / Answer

14)   1 mile = 1609.34 m

        1 yard = 0.9144 m

Then length of marathon run = 26 mi 385 yd = 26*1609.34 + 385*0.9144 = 42194.94 m

15) 1 mile = 1609.34 m

Then distance = 3273 miles = 3273*1609.34 = 5267383 m

16) option 4) is correct.

Acceleration = a = v^2/x = (m/s)^2/m = m/s^2

17) option 1) is correct.

Volume = V = L^3

Then dimension of C will be = L^3/T^4

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