two ice skaters stand together. they push off and travel directly away from each

Question

two ice skaters stand together. they push off and travel directly away from each other, the boy with a velocity of v= 0.66 m/s to the left. if the bou weighs 709 N and girl weighs 476 N, what is the girls velocity, after push off? (consider it to be frictionless. enter magnitude only.) two ice skaters stand together. they push off and travel directly away from each other, the boy with a velocity of v= 0.66 m/s to the left. if the bou weighs 709 N and girl weighs 476 N, what is the girls velocity, after push off? (consider it to be frictionless. enter magnitude only.) two ice skaters stand together. they push off and travel directly away from each other, the boy with a velocity of v= 0.66 m/s to the left. if the bou weighs 709 N and girl weighs 476 N, what is the girls velocity, after push off? (consider it to be frictionless. enter magnitude only.) two ice skaters stand together. they push off and travel directly away from each other, the boy with a velocity of v= 0.66 m/s to the left. if the bou weighs 709 N and girl weighs 476 N, what is the girls velocity, after push off? (consider it to be frictionless. enter magnitude only.)

Explanation / Answer

Using momentum conservation

Pi = Pf

Pi = 0, Since initially both boy and girl are stationary

So,

Pf = 0

Mb*Vb + Mg*Vg = 0

Vg = - (Mb/Mg)*Vb

Mb = Wb/g

Mg = Wg/g

So,

Vg = -(Wb/Wg)*Vb

Vg = -(709/476)*0.66

Vg = -0.983 m/sec

-ve sign means direction will be to the right.

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