The following is a small stretch of nucleotide sequence from a bacterial mRNA: 5
ID: 166226 • Letter: T
Question
The following is a small stretch of nucleotide sequence from a bacterial mRNA: 5’ – GGGCCCUGAUGUAACAUAGAUAGG – 3’
A) What is the sequence of the DNA template from which it was transcribed? (indicate polarity).
3' - CCC GGG ACT ACA TTG TAT CTA TCC - 5'
Need Answer to B
B) Use the genetic code table of your textbook to determine the amino acid sequences encoded by all three reading frames. Use an asterisk (*) to indicate any stop codons you encounter and continue translating beyond them.
Nucleotide seq: 5’ – G G G C C C U G A U G U A A C A U A G A U A G G – 3’
RF1:
RF2:
RF3:
C) Would the same information be encoded by the RNA sequence that is complementary to the sequence given above?
No, original sequence:
GGG CCC UGA UGU AAC AUA GAU AGG
And this is the sequence complimentary to it:
CCC GGG ACU ACA UUG UAU CUA UCC
The complementary sequence has the exact opposite bases as the original, its not possible they could code for the same peptide chains.
D) Considering that the RNA sequence is a fragment of an mRNA, answer the questions below and BRIEFLY (10 words or less) explain your reasoning.
i) Could this RNA be from the beginning of a protein coding region?
No, there is no start codon (UAC)
ii) The middle?
Yes it could, there is nothing preventing it from being there
iii) The end?
No, there is no stop codon (UTT, AUC, ACU).
Second letter A G UAU UGU U UUCIPhe UCC Sr Tyr UGC UGC jcys UAC UUG Leu UCA Ser UUA UAA Stop UGA Stop A UCG UAG Stop UGG Trp CCA/Pro CAC His CGU CAU1His CGC Arg A . CUU CCU CUAiLeu CCC CUC Leu CCA CCCI Pro CAA]Gln CGG CAGIGIn CGA Arg A C CUA CUG CCG ACU AGC Ser U AUU AAU AGU - .. AUC Ile ACC AAC fAsn AUA ACA AAA AGA AAGfLys AGG Arg AUG Met ACGJ GCA/Ala GAC Asp GGU GAULAsp GGC Gly A GUU GCU GUC Val GCA GUA Val GCC GCC Ala GAA] Glu GGG GAG Glu GGAiGly G GUG GCG Third letter UCAG UCAG UCAG UCAG -1111 (11111 ] J UUUU CCCC AAAA GGGG ns J UCAG UCAG AAAA AAAA AAAA AAAA GGGG UUUU CCCC AAAA GGGG eu PL UUUU CCCC AAAA GGGG A Jamal 1S1HExplanation / Answer
RF1: Gly-Pro-*-Cys-Asn-Ile-Asp-Arg
RF2: Gly-Pro-Asp-Val-Thr-*-Ile
RF3: Ala-Leu-Met-*-His-Arg-*
This is the sequence of amino acids obtained considering the 3 reading frames.
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