The electric field in a current-carrying wire can be modeledas the electric fiel

Question

The electric field in a current-carrying wire can be modeledas the electric field at the midpoint between two charged rings.Model a 3.00-mm-diameter aluminum wire as two3.00-mm-diameter rings 2.00 mm apart. What is the current in the wire after 10.0 electrons aretransferred from one ring to the other? The electric field in a current-carrying wire can be modeledas the electric field at the midpoint between two charged rings.Model a 3.00-mm-diameter aluminum wire as two3.00-mm-diameter rings 2.00 mm apart. What is the current in the wire after 10.0 electrons aretransferred from one ring to the other?

Explanation / Answer

E = k q x / (x2 +a2)3/2     the electricfield at distance x from ring of radius a carrying charge q E = 9 * 10 E9 * 20 * 1.6 * 10E-19 * .001 / (.00152+ .0012)    the field due to the tworings add E = 4.92 * 10E-3 N/c F = E q      force on charg q due tofield E W = 2 F x   = 2 E q x work donemoving charge q distance x in field E V = W / q = 2 E x    potential difference involts V = 2 * 4.92 * 10E-3 * .001 = 9.84 * 10E-6 V I = V / R R = L / A = 2.83 * 10E-6 ohm- cm * .2cm / ( *.152 cm2) = 8 * 10E-6 ohms I = 9.84 / 8 = 1.23 amps

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.