The electric field at the point x=5.00cm and y=0 points in thepositive x directi

Question

The electric field at the point x=5.00cm and y=0 points in thepositive x direction with a magnitude of 10.0 N/C. At thepoint x=10.0cm and y=0 the electric field points in the positive xdirection with a magnitude of 13.0 N/C. Assume this elecricfield is produced by a single point charge. A) Find chargelocation, B)sign, and C)magnitude of the charge. For part A) i got 45.67 cm= 0.4567m For part B) negative For part C) this is what i did and it is still telling me thatits wrong. Where am i going wrong. please help!
kq=(10.0N/C)(x-0.05m)^2 q=1/k(10.0N/C)(0.4567m-0.05m)^2    =1/8.99*10^9 (10.0N/C)(0.4567m-0.05)^2    = -1.84pC For part A) i got 45.67 cm= 0.4567m For part B) negative For part C) this is what i did and it is still telling me thatits wrong. Where am i going wrong. please help!
kq=(10.0N/C)(x-0.05m)^2 q=1/k(10.0N/C)(0.4567m-0.05m)^2    =1/8.99*10^9 (10.0N/C)(0.4567m-0.05)^2    = -1.84pC

Explanation / Answer

   C.   E   =   (1/40)* q / r2          10.0   N/C   =   8.99* 109 * q / ( 0.4567 - 0.05)2    q   =   10 *(0.4567 - 0.05)2 / 8.99 *109   =   1.84 *10-10   C   =   0.184   nC   or   184   pC    q   =   10 *(0.4567 - 0.05)2 / 8.99 *109   =   1.84 *10-10   C   =   0.184   nC   or   184   pC

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