When two unknown resistors are connected in series with abattery, the battery de
ID: 1663142 • Letter: W
Question
When two unknown resistors are connected in series with abattery, the battery delivers 240 W andcarries a total current of 5.00 A. For the same total current,50.0 W is delivered when the resistors areconnected in parallel. Determine the values of the tworesistors. (the following is a different question all together) Two identical parallel-wired strings of 40 bulbs are connected to each other in series. If theequivalent resistance of the combination is 120.0 when it is connected across a potentialdifference of 120.0 V, what is the resistance of each individualbulb? When two unknown resistors are connected in series with abattery, the battery delivers 240 W andcarries a total current of 5.00 A. For the same total current,50.0 W is delivered when the resistors areconnected in parallel. Determine the values of the tworesistors. (the following is a different question all together) Two identical parallel-wired strings of 40 bulbs are connected to each other in series. If theequivalent resistance of the combination is 120.0 when it is connected across a potentialdifference of 120.0 V, what is the resistance of each individualbulb?Explanation / Answer
Firstproblem : Power, P = I2 R Case I: P = 240W I = 5 A Rs = P /I2 = 9.6 R1 + R2 =9.6 .........(1) Case II: P = 50W I = 5 A Rp = P / I2 = 2 [ R1 * R2 / ( R1 +R2 ) ] = 2 ..............(2) Solve (1)and (2) for R1 and R2 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Secondproblem: No. of bulbs ineach string, n = 40 Req = 120 Resistance of eachstring = 2 Req ( since they are in parallel ) = 240 Let R = resistance ofeach bulb n R = 240 Resistance of each bulb,R = 240 / 40 = 6
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