Two small plastic spheres are given positive electricalcharges. When they are a

Question

Two small plastic spheres are given positive electricalcharges. When they are a distance of R apart, the repulsive forcebetween them has a magnitude of F. Question a What is the charge on each sphere if the two charges areequal? part b What is the charge on first sphere if it has four times thecharge of the other? Hi I need someone to show me the steps and formulas, Solvingwith variables is what we need to follow. Can you helpASAP???? Two small plastic spheres are given positive electricalcharges. When they are a distance of R apart, the repulsive forcebetween them has a magnitude of F. Question a What is the charge on each sphere if the two charges areequal? part b What is the charge on first sphere if it has four times thecharge of the other? Hi I need someone to show me the steps and formulas, Solvingwith variables is what we need to follow. Can you helpASAP????

Explanation / Answer

(a). Force = F distance = R Let the charge on each sphere be q we know F = K q^ 2 / R ^ 2 from this charge on each sphere q = R [ F /K ] where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2 (b). Force = F distance = R Let the charge on second sphere be q then charge onfirst sphere beq ' = 4q we know F = K q* 4q / R ^ 2                   = 4Kq^ 2 / R ^ 2 from this charge on second sphere q = ( R /2 )[ F / K ] where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2 Therefore charge on 1 st sphere =4q = 2R [ F / K] distance = R Let the charge on second sphere be q then charge onfirst sphere beq ' = 4q we know F = K q* 4q / R ^ 2                   = 4Kq^ 2 / R ^ 2 from this charge on second sphere q = ( R /2 )[ F / K ] where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2 Therefore charge on 1 st sphere =4q = 2R [ F / K]

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