Hi, I need help remember the process of solving vectors. So say we have 2 point

Question

Hi, I need help remember the process of solving vectors. So say we have 2 point charges (q1 and q2) bothpositive at (a) and (-a) on the y-axis and those are positive,then we have a -Q 3 (negative) on the x-axis at 3m orsimply (x) whichever is easier to explain. Now I want to know the force of q1 on Q3 and the force of q2on Q3, and then the total. I think the force points towards q1 and q2 from Q3 since it isattractive. I need help step by step of solving the x-component as they-component will cancel. what I have forgotten is how to dealwith the angle below the x-axis and I also think to find the forcewe use F1on3(sub x) = F1*cos(), cos is justadj/hyp and then F2on3=F2*cos() Does someone have time to give me a refresher on vectorsolving? And the difference of the forces if we have two positiveor two negative charges placing forces on each other. Hi, I need help remember the process of solving vectors. So say we have 2 point charges (q1 and q2) bothpositive at (a) and (-a) on the y-axis and those are positive,then we have a -Q 3 (negative) on the x-axis at 3m orsimply (x) whichever is easier to explain. Now I want to know the force of q1 on Q3 and the force of q2on Q3, and then the total. I think the force points towards q1 and q2 from Q3 since it isattractive. I need help step by step of solving the x-component as they-component will cancel. what I have forgotten is how to dealwith the angle below the x-axis and I also think to find the forcewe use F1on3(sub x) = F1*cos(), cos is justadj/hyp and then F2on3=F2*cos() Does someone have time to give me a refresher on vectorsolving? And the difference of the forces if we have two positiveor two negative charges placing forces on each other.

Explanation / Answer

F1 = k*q1*Q3/(a2 + x2) F2 = k*q2*Q3/(a2 + x2) cos = x/(a2 + x2), sin =a/(a2 + x2) assume x > 0 Fx = -(F1cos + F2cos) = -(F1 + F2)cos= -k(q1 + q2)*Q3*x/(a2 +x2)3/2 Fy = F1sin - F2sin = (F1 - F2)sin =k(q1 - q2)*Q3*a/(a2 + x2)3/2

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