Compute your average velocity in the following two cases. (a) You walk 77.3 m at

Question

Compute your average velocity in the following two cases. (a) You walk 77.3 m ata speed of 1.22 m/s and then run 77.3 m ata speed of 3.05 m/s along a straight track.
m/s

(b) You walk for 1.99 min at a speed of1.22 m/s and then run for 1.99 min at 3.05m/s along a straight track.
m/s

(c) Graph x versus t for both cases and indicatehow the average velocity is found on the graph. (a) You walk 77.3 m ata speed of 1.22 m/s and then run 77.3 m ata speed of 3.05 m/s along a straight track.
m/s

(b) You walk for 1.99 min at a speed of1.22 m/s and then run for 1.99 min at 3.05m/s along a straight track.
m/s

(c) Graph x versus t for both cases and indicatehow the average velocity is found on the graph.

Explanation / Answer

average velocity is x/t. Part A) find the time for walking 77.3m at 1.22m/s: x=v*t t=x/v=77.3/1.22=63.4s find the time for running at 3.05m/s: t=x/v=77.3/3.05=25.3s now find the average velocity: x/t=(77.3+77.3)/(63.4+25.3)=1.74m/s Part B) 1.99 min is 60*1.99=119.4s find the distance traveled: x=v*t=1.22*119.4=145.7m x=v*t=3.05*119.4=364.2m now find the average velocity: x/t=(145.7+364.2)/(119.4+119.4)=2.14m/s Part C) I think you can draw the graphs on your own, but the way to findaverage velocity from the graph would be take the last x-value (thetotal distance traveled) and divide by the last t-value (the totaltime that it took).

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.