Compute your average velocity in the following two cases. (a) You walk 73.4 m at

Question

Compute your average velocity in the following two cases. (a) You walk 73.4 m ata speed of 1.22 m/s and then run 73.4 m ata speed of 3.05 m/s along a straight track.
1 m/s

(b) You walk for 1.73 min at a speed of1.22 m/s and then run for 1.73 min at 3.05m/s along a straight track.
2 m/s

(c) Graph x versus t for both cases and indicatehow the average velocity is found on the graph. (Do this on paper.Your instructor may ask you to turn in this graph.) (a) You walk 73.4 m ata speed of 1.22 m/s and then run 73.4 m ata speed of 3.05 m/s along a straight track.
1 m/s

(b) You walk for 1.73 min at a speed of1.22 m/s and then run for 1.73 min at 3.05m/s along a straight track.
2 m/s

(c) Graph x versus t for both cases and indicatehow the average velocity is found on the graph. (Do this on paper.Your instructor may ask you to turn in this graph.)

Explanation / Answer

average velocity is x/t. Part A) find the time for walking 73.4m at 1.22m/s: x=v*t t=x/v=73.4/1.22=60.2s find the time for running at 3.05m/s: t=x/v=73.4/3.05=24.1s now find the average velocity: x/t=(73.4+73.4)/(60.2+24.1)=1.74m/s Part B) 1.73 min is 60*1.73=103.8s find the distance traveled: x=v*t=1.22*103.8=126.6m x=v*t=3.05*103.8=316.6m now find the average velocity: x/t=(126.6+316.6)/(103.8+103.8)=2.13m/s Part C) I think you can draw the graphs on your own, but the way to findaverage velocity from the graph would be take the last x-value (thetotal distance traveled) and divide by the last t-value (the totaltime that it took).

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