Chapter 18 P. 63 q1 = +4.0x10-6 at x1 = +4.0 cm q2 = +4.0x10-6 at x2 = -4.0 cm q

Question

Chapter 18 P. 63 q1 = +4.0x10-6 at x1 = +4.0 cm q2 = +4.0x10-6 at x2 = -4.0 cm q3 = +1.0x10-6 at y3 = +5.0 cm q4 = -4.0x10-6 at y4 = +7.0cm I need to find Electric Field (magnitude & direction) atthe orgin. (-8.99E9) (1.0E-6) / (5.0E-2)2 + (-8.99E9) (-4.0E-6) /(7.0E-2)2 -3.60E6 + -7.34E6 -1.09E7 Please tell me what went wrong in detail Chapter 18 P. 63 q1 = +4.0x10-6 at x1 = +4.0 cm q2 = +4.0x10-6 at x2 = -4.0 cm q3 = +1.0x10-6 at y3 = +5.0 cm q4 = -4.0x10-6 at y4 = +7.0cm I need to find Electric Field (magnitude & direction) atthe orgin. (-8.99E9) (1.0E-6) / (5.0E-2)2 + (-8.99E9) (-4.0E-6) /(7.0E-2)2 -3.60E6 + -7.34E6 -1.09E7 Please tell me what went wrong in detail

Explanation / Answer

Ok, since q1 and q2 are equal in magnitude and at 4 cm on oppositesides of the origin, they cancel out since they both exert the sameE field in different directions Now we just need to add the electric fields from q3 and q4 E3=k(1x10^-6)/(0.05m)^2 = 0.0004k E4=k(4x10^-6)/(0.07m)^2=0.000816k add the two gives us 0.001216 k, which equals 1.093x10^7N/C Perhaps just your sign is wrong? the constant k is positive,notnegative

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