I have a problem that I just cant grasp. Had a similiar one ontest and did not h
ID: 1665916 • Letter: I
Question
I have a problem that I just cant grasp. Had a similiar one ontest and did not have a clue. Could someone please walk me thruthis problem in the simpilist way, not skipping steps but showinghow different equations are worked thru, thanks for any help. A 300 Kg boat is moving at a constant speed of 3.0 m/s in adirection 30 degrees north of east. Suddenly, the boat feels aforce due to the wind which is directed 45 degrees north of eastand has a magnitude of 100 N. After 10 seconds, what is thevelocity vector of the boat? I have a problem that I just cant grasp. Had a similiar one ontest and did not have a clue. Could someone please walk me thruthis problem in the simpilist way, not skipping steps but showinghow different equations are worked thru, thanks for any help. A 300 Kg boat is moving at a constant speed of 3.0 m/s in adirection 30 degrees north of east. Suddenly, the boat feels aforce due to the wind which is directed 45 degrees north of eastand has a magnitude of 100 N. After 10 seconds, what is thevelocity vector of the boat?Explanation / Answer
initial velocity, vi = 3m/s (300due north ofeast) = 3cos300i +3sin300 j = 3*3/2 i+3*1/2 j m/s force of the wind, F = 300 N(450 due north of east) =300*3/2 i+300*1/2 j N mass of the boat, m = 100 Kg acceleration of the boat, a = F/m =3*3/2 i+3*1/2 j m/s2 velocity aftertime, t ,vf =vi +a*t velocityafter time 10s is, v = 33/2 i+3/2 j+10*( 33/2i+3/2j) =28.578i+16.6j m/s
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