A 0.500 kg ball falls directly downonto concrete, hitting it with a speed of 12.
ID: 1666389 • Letter: A
Question
A 0.500 kg ball falls directly downonto concrete, hitting it with a speed of 12.5 m/s and rebounding directly upward with a speedof 3.00 m/s. Extend a y axis upward (a) What is the change in the ball'smomentum?(b) What is the impulse on the ball? (c) What is the impulse on theconcrete?
A 0.500 kg ball falls directly downonto concrete, hitting it with a speed of 12.5 m/s and rebounding directly upward with a speedof 3.00 m/s. Extend a y axis upward (a) What is the change in the ball'smomentum?
(b) What is the impulse on the ball? (c) What is the impulse on theconcrete?
Explanation / Answer
a) the change is momentum M=12,5*m+3*m=15,5m=7,75(kgm/s) b) the impluse on the ball is equal to the change of momentum =7,75kgm/s c) the impluse on the concrete is equal to the impulse on theball(newton 3rd law) so it is also 7,75kgm/s
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