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A 0.50-kg bomb is sliding along an icy pond (frictionless surface) with a veloci

ID: 1776527 • Letter: A

Question

A 0.50-kg bomb is sliding along an icy pond (frictionless surface) with a velocity m's to the west. The bomb explodes into two pieces. piece moves south at 4. piece? A) 4.0 m/s north, 0 m/s B) 2.7 m/s north, 3.3 m/s west C) 4.0 m/s north, 2.7 m/s west D) 0 m/s, 2.0 m/s east E) 4.0 m/s north, 2.0 m/s east 5. After the explosion, a 0.20-kg 6. A 0.10-kg cart traveling in the positive x direction at 10.0 m/s collides with a 0.30-kg What is the velocity of the 0.10-kg cart after the cart at rest. The collision is elastic. collision? A) +2.5 m/s B) -2.5 m/s C) +5 m/s D) -5 m/s E) +3.3 m/s 7. A wheel with a 0.10-m radius is rotating at 35 rev/s. It then slows uniformly to 15 rev/s over a 3.0-s interval. What is the angular acceleration of a point on the wheel? A) -2.0 rev/s2 B) 0.67 rev/s C) -6.7 rev/s2 D) 42 rev/s E) -17 revis 8. An airplane engine starts from rest; and 2 seconds later, it is rotating with an angular speed of 420 rev/min. If the angular acceleration is constant, how many revolutions does the propeller undergo during this time? A) 7 B) 14 C) 21 D) 49 E) 150 9. A wheel, originally rotating at 126 rad/s undergoes a constant angular deceleration of 5.00 rad's. What is its angular speed after it has turned through an angle of 628 radians? A) 15 rad/s B) 19 rad/s C) 98 rad/s D) 121 rad/s E) 150 rad/s

Explanation / Answer

5. Initial mometum = mv = 1 Kg.m/sec along west

Final mometum = along south is .8m/sec

Since initial mometum was 0 along north/south, the velocity of the .3 Kg block is: 2.7 m/sec north and 3.3 m/sec along west

6. The velocity is: 1/.4 = .25 m/sec along x (using momentum conservation)

7. The angular acceleration is:

-20/3 = -6.67 rev/sec

8. 420 rev/min = 7 rev /sec

acceleration = 7/2 = 3.5 rev/sec

In 2 secs, it goes 7 revolutions

9. v^2 = u^2 - 2 * acc * angle

u = 126, angle = 628, acc = 5

v = 98 rad/sec