A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.

Question

A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. (a) What is the capacitance of this cable?
C = 1 nF

(b) What is the potential difference between the two conductors?Assume the region between the conductors is air.
V = 2 kV A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. A 57.0 m length of coaxial cable has an innerconductor that has a diameter of 2.58 mm and carries a charge of8.10 µC. The surrounding conductor has an inner diameter of7.27 mm and a charge of -8.10 µC. (a) What is the capacitance of this cable?
C = 1 nF

(b) What is the potential difference between the two conductors?Assume the region between the conductors is air.
V = 2 kV (a) What is the capacitance of this cable?
C = 1 nF

(b) What is the potential difference between the two conductors?Assume the region between the conductors is air.
V = 2 kV (a) What is the capacitance of this cable?
C = 1 nF

(b) What is the potential difference between the two conductors?Assume the region between the conductors is air.
V = 2 kV

Explanation / Answer

the capacitance of this capacitor is C=2*0*L/ln(r2/r1)= 3.1nF (b)the potential difference : V=Q/C=2.65 kV

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