A 55mL sample of 1 M hydrobromic acid solution was diluted to 100 ml and poured

Question

A 55mL sample of 1 M hydrobromic acid solution was diluted to 100 ml and poured into the caorimeter from problem #1. The inital temp. of the hydrobromic acid in the calorimeter was 20.1C. When 2.8102 grams of solid KOH was added to the hydrobromic acid in the calorimeter, a neutralization reaction occured, and the temperature of the resulting 0.5M KBr solution rose to 37.0C. the total mass of the solution was 107.3482 grams, and the specific hear of the solution was 4.05 Joules grams

Determine the number of moles of water formed in the reaction.

Determine the amount of heat absorded by the solution and calorimeter

Determine the heat of reaction per mole of water formed

Explanation / Answer

For the given neutralization reaction,

moles of water formed = 2.8102 g/56.1056 g/mol = 0.05 mols

Heat absorbed by solution = -mCpdT = -107.3482 x 4.05 x (37 - 20.1) = -7.35 kJ

Heat absorbed by the calorimeter = + 7.35 kJ

Heat of reaction per mole of water = 7.35 kJ/0.05 mol = 147 kJ/mol

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