A 920 N , what is the maximum allowable speed of therock? b) At this maximum spe

Question

A 920 N , what is the maximum allowable speed of therock? b) At this maximum speed, what angle does the string make with thehorizontal? I got part a by using the formula a=v^2/r as well as F=ma andsolved for v to find v=14m/s but for part b i dont understand how an angle is formed if it isswung in a horizontal circle. Any help would be greatly appreciated. m -long string. a) the breaking strength of the string is 130 g rock is whirled in a horizontal circle at theend of a 1.4

Explanation / Answer

     a) at breaking point              T = mv2 / R              ==> 130 = 0.92 * v 2 / 1.4              ==> v = 14.06 m/s b) tan = v2 / Rg           =tan-1 (14.41) = 86.03o Therefore the string makes angle with the horizontalis               = 90 - 86.03 = 3.96o

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