A small piece of dust of mass m = 3.3 µg travels through an electric aircleaner

Question

A small piece of dust of mass m = 3.3 µg travels through an electric aircleaner in which the electric field is 525 N/C. The electric force on the dust particleis equal to the weight of the particle. (a) What is the charge on the dustparticle?
1 C

(b) If this charge is provided by an excess of electrons, how manyelectrons does that correspond to?
2 electrons
(a) What is the charge on the dustparticle?
1 C

(b) If this charge is provided by an excess of electrons, how manyelectrons does that correspond to?
2 electrons

Explanation / Answer

a) F = Eq        == > mg = Eq        ==> q = mg / E                   = 3.3 x 10-9 * 9.8 / 525                   = 61.6x 10-12 C b) q = ne      ==> n = q / e                = 61.6 x 10-12 / 1.6 x 10-19                = 38.5 x 107

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