L=2m & is the length of a string attached to apole & 30 o is the distance betwee

Question

L=2m & is the length of a string attached to apole & 30o is the distance between thepole & the string and 1kg is the mass of the ball at theend of the string swinging with uniform motion around the polecounterclockwise I understand Fr = Tsin mar =mv2/r = mr2 Ft = mat = 0 Fz = Tcos - mg = 0 (become) T =mg/cos = 11.3N (when m=1kg & =30o) I dont understand why: T = 2/ = 2(mLsin/Tsin) =2(Lcos/g) = 2.6s L=2m & is the length of a string attached to apole & 30o is the distance between thepole & the string and 1kg is the mass of the ball at theend of the string swinging with uniform motion around the polecounterclockwise I understand Fr = Tsin mar =mv2/r = mr2 Ft = mat = 0 Fz = Tcos - mg = 0 (become) T =mg/cos = 11.3N (when m=1kg & =30o) I dont understand why: T = 2/ = 2(mLsin/Tsin) =2(Lcos/g) = 2.6s Ft = mat = 0 Fz = Tcos - mg = 0 (become) T =mg/cos = 11.3N (when m=1kg & =30o) I dont understand why: T = 2/ = 2(mLsin/Tsin) =2(Lcos/g) = 2.6s

Explanation / Answer

is T tension or torque?

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