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When its coil rotates at a frequency of 286 Hz, a certain generator has a peak e

ID: 1669526 • Letter: W

Question

When its coil rotates at a frequency of 286 Hz, a certain generator has a peak emf of71 V. (a) What is the peak emf of the generator whenits coil rotates at a frequency of 48Hz?
Enter anumber. 1 V

(b) Determine the frequency of the coil's rotation when the peakemf of the generator is 189 V.
Enter anumber. 2 Hz (a) What is the peak emf of the generator whenits coil rotates at a frequency of 48Hz?
Enter anumber. 1 V

(b) Determine the frequency of the coil's rotation when the peakemf of the generator is 189 V.
Enter anumber. 2 Hz Enter anumber. Enter anumber.

Explanation / Answer

Given       f1   = 286 Hz    1   = 71 V a) f2   = 48 Hz       2   =? we know that    peak emf of the generator    = NB A (2f )        from the aboveformula             e m f is directly proportional to the frequency                     1 / 2 = f1 / f2                2 = 1 f2 /f1                       = 71 * 48 / 286                        = 11.91 V f2   = ..........Hz       2   = 189V we know that    peak emf of the generator    = NB A (2f )        from the aboveformula             e m f is directly proportional to the frequency                     1 / 2 = f1 / f2                f2 = f1 2 /1                       =286 * 189 / 71                        = 761.323 Hz

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