(a) What is the mass of the second particle? kg (b) What is the magnitude of the

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• • Section 21.4 Coulomb's Law

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We know that            F = ke Q1Q2 / r2 Given that             Q1 = Q2 = Q ==> F = ke Q2 /r2         ...........1 And we also know that           F =ma     ...........2 Therefore from above two equations we can write           m1 a1 = ke Q2 / r2 ==> Q2 = m1 a1r2 / ke               = 6.3 x 10-7 * 7.0 * (2.3 x 10-3)2 / 9 x 109               = 25.91 x 10-22 ==> Q = 5.091 x 10-11C Therefore using the same procedure and we can calculate themass of second particle is                 m2 = ke Q2 / r2a2                      = 9 x 109 * (25.91 x 10-22) / (2.3 x10-3)2 * 9.0                      = 4.897 x 10-7 kg a) m2 = 4.897 x 10-7 kg b) Q = 5.091 x 10-11 C

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