(a) What is the length of a simple pendulum that oscillates with a period of 2.0

Question

(a) What is the length of a simple pendulum that oscillates with a period of 2.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

(b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

Explanation / Answer

a.T = 2*pi* (l/g)^0.5

L = (T^2) * g / (4*pi^2)

so,

1.L = 0.9929 m

2. L = 0.3749 m

b T = 2*pi* (m/k)^0.5

=> m= (T^2) * k / (4*pi^2)

so,

3.m = 2.026 kg

4. m = 2.026 kg

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