(a) What is the length of a simple pendulum that oscillates with a period of 2.4

Question

(a) What is the length of a simple pendulum that oscillates with a period of 2.4 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

Le = __________ m

Lm= __________ m

(b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.4 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

me = ________ kg

mm= ________ kg

Explanation / Answer

a.) T = 2*3.14*root(l/g)

2.4 = 2*3.14*root(Le/9.81)

Le = 1.43 m

2.4 = 2*3.14*root(Lm/3.7)

Lm = .54 m

b.) 2*3.14/T = root(k/m)

2*3.14/2.4 = root(20/Me)

Me = 2.92Kg

similarly

same

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