puck m=0.5kg UCM on fric freehorizontal table. Angular freq. of mass = 4sec^-1(c

Question

   puck m=0.5kg UCM on fric freehorizontal table. Angular freq. of mass = 4sec^-1(counterclock) radius of circular motion =0.8m radius is fixed as student hold string in place. The studentpulls string down 0.5m and holds it again in place. What work didhe do?    puck m=0.5kg UCM on fric freehorizontal table. Angular freq. of mass = 4sec^-1(counterclock) radius of circular motion =0.8m radius is fixed as student hold string in place. The studentpulls string down 0.5m and holds it again in place. What work didhe do?

Explanation / Answer

Given that      m = 0.5 kg      = 4s-1       r = 0.8       X = 0.5m We know that workdone = F.X = m r 2 X = 0.5 * 0.8 *16 * 0.5 = 3.2J

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